lg8+2lg5-lg2+(-1/27)^-1/3-【(根号2)-1】+3^log的底数9(2)=
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lg8+2lg5-lg2+(-1/27)^-1/3-【(根号2)-1】+3^log的底数9(2)=lg8+2lg5-lg2+(-1/27)^-1/3-【(根号2)-1】+3^log的底数9(2)=lg
lg8+2lg5-lg2+(-1/27)^-1/3-【(根号2)-1】+3^log的底数9(2)=
lg8+2lg5-lg2+(-1/27)^-1/3-【(根号2)-1】+3^log的底数9(2)=
lg8+2lg5-lg2+(-1/27)^-1/3-【(根号2)-1】+3^log的底数9(2)=
lg8+2lg5-lg2+(-1/27)^-1/3-【(根号2)-1】+3^log的底数9(2)
= lg8+lg25-lg2+(-27)^1/3-【(根号2)-1】+3^log的底数3(√2)
= lg(8*25/2)+(-3)-√2+1+√2
= lg100-3+1
=2-2
=0
化简[(1-lg5)^2+lg2乘lg5]/lg8
lg2+lg5=?1-lg2=?1-lg5=?2lg5+2/3lg8+lg5*lg20+(lg2)2=?
3lg5+lg8+(lg2)^0+(27/64)^-1/3
lg500+(lg8/5)-(1/2lg64)+50(lg2+lg5)^2
(lg8+lg1000)lg5+3(lg2)^2+lg^-1+lg0.006
(lg8+lg100)lg5+3(lg2)^2+lg6^-1+lg0.006
lg500+lg8/5–1/2lg64+50(lg2+lg5)
lg500+lg500+lg8/5-1/2lg64+(lg2+lg5)(lg2+lg5)化简
计算:(lg2)2+3lg5+lg5(1+lg2)+lg8+log2(5)log5(4)
(lg2)^3+(lg5)^3+lg5*lg8=(lg2+lg5)[(lg2)^2-lg2*lg5+(lg5)^2]+lg5*lg2^3=1[(lg2)^2-lg2*lg5+(lg5)^2]+3lg5*lg2=(lg2)^2+(lg5)^2+2lg5*lg2=(lg2+lg5)^2=1网上看了看答案,可是第一步没有看懂.求得出第一步的过程,
对数lg2*lg5=?2lg(5)+2/3 lg8+lg5*lg20+lg2 =lg5^2+lg8^(2/3)+lg5*(lg4+lg5)+lg2 =lg100+lg5+2lg2*lg5+lg2 =2+(lg5+lg2) =2+1 =3 第二个等号lg5*(lg4+lg5)为什么=lg5+2lg2*lg5
lg5^2+2/3lg8+lg5*lg20+lg2^2
lg5^2+lg8^2/3+lg5*lg20+(lg2)^2=?
(lg5)平方+2/3lg8+lg5乘lg20+(lg2)平方
3lg2+2lg5+lg5乘以lg8怎样算
lg5²+2/3lg8+lg5*lg20+(lg2)²
lg5²+2/3lg8+lg5×lg20+(lg2)²
计算下列公式 (1)(2lg2+lg3)/(1+1/2lg0.36+1/3lg8) (2) lg5^2+2/3lg8+lg5*lg20+(lg2)^2