求怎样解极限lim(x→1)[(3/1-x三次方)-(1/1-x)]
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 17:07:30
求怎样解极限lim(x→1)[(3/1-x三次方)-(1/1-x)]求怎样解极限lim(x→1)[(3/1-x三次方)-(1/1-x)]求怎样解极限lim(x→1)[(3/1-x三次方)-(1/1-x
求怎样解极限lim(x→1)[(3/1-x三次方)-(1/1-x)]
求怎样解极限lim(x→1)[(3/1-x三次方)-(1/1-x)]
求怎样解极限lim(x→1)[(3/1-x三次方)-(1/1-x)]
答案是1
但你的表达太不规范了
首先1-x*x*x=(1-x)(1+x+x*x)
所以两边同分,相减 ,分子为2-x-x*x=-(x*x+x-2)=-(x-1)(x+2)
约分之后为(x+2 )/(1+x+x*x)
当x=1时 ,原试=1
求怎样解极限lim(x→1)[(3/1-x三次方)-(1/1-x)]
lim(1-x)^3/x 求极限~
求极限lim x→∞ (x/(1+x))^x
求极限lim Ln(1+x) /x > .< x→0
求极限lim(1-2/x+3/x^2)^x
求极限 lim [(3+x)/(6+x)]^[(x-1)/2]= x→∞求极限 lim [(3+x)/(6+x)]^[(x-1)/2]=x→∞
求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限
求极限lim(x→∞)(2x/3-x)-(2/3x)求极限lim(x→5)根号(x-1)-2/x-5
lim (1-1/3x)^x x→∞ 求极限lim(1+1/x)^x=e
求极限lim(x→0)x²/1-cosx
求极限:lim(x→+∞)[ln(x+1)-lnx]
求极限lim(x→0) cos(1/x)
求lim(1-cos2x)/x^2极限,x→0
求极限lim(x→0)(cosx-(1/x))
求极限lim x→0 (1/xsinx+xsin1/x)
求极限lim(x→0) (1-sinx)^(2/x)
lim x→∞ xsin(1/x)求极限
求极限 lim(x→0)(1-sinx)^(2/x)