log2^5+3=
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log2^5+3=log2^5+3=log2^5+3=lg(2^5)+3=3+5lg2≈4.50514998
log2^5+3=
log2^5+3=
log2^5+3=
lg(2^5)+3=3+5lg2≈4.50514998
log2^5+3=
log2 3/log2 5等于log2 3-log2 5么?
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
求值:log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的?
LOG2^3=A,LOG2^5=b,则log2^9/5值是多少
log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙!
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X
(log2 9)/(log2 8) = 2/3(log2 3)
log2^(4^7*2^5)+log2^6-log2^3
3^(log2 (5))-5^(log2(3))
log2 5/4+log2 5=多少,
5^log30*3^log2=15
log2(x^2-3)=5 计算
log2(5) ×log5(8)=3步骤
log2(3)+log3(5)+log3(2)=?
2log2^3=
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)