log8 4=?2^(log2 3-2)=?

log8 4=?2^(log2 3-2)=? 若log2(log8 m)=log8(log2 m),则(log2 m)^2 (log8 9/log2 3)=? log8 (log2 4根号2)的值是是log8*(log(2 4根号2)) log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9 求值：(log4(3)+log8(3))(log3(2)+log3(4))-log2(64) (log2(3)+log8(9))x(log3(4)+log9(8)+log3(2)) 求（log2^3+log8^9)(log3^4+log9^8+log3^2)的值 log8(9)*log2(3) 你说lo5*lo8=3 log8(2）*log2(64) 依你的算法是log8(2)*4=1*log4(64)=3 你认为是对的吗 (log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?.. [log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)][log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2) (log4＾3+log8＾3)(log3＾2+log9＾2)+log2＾(32)的1/4次方 对数的平方如何算?log8^9=log2^3^3^2是怎么得来的? 求(log2^3+log8^9) 我想知道为什么 log(2^2) 3=1/2*log2 3 log8 3=log(2^3) 3=1/3*log2 3 设A={x|2(log1/2^x)^2-21*log8^x+3≤0}若当x∈A时f（x）=log2 ^2^x/a*log2 x/4的最大值为2,求a 设A={x|2(log1/2^x)^2-21*log8^x+3≤0}若当x∈A时f（x）=log2 ^2^x/a*log2 x/4的最大值为2,求a说清楚,一小时