(log8 9/log2 3)=?

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(log89/log23)=?(log89/log23)=?(log89/log23)=?方法一(log89/log23)=(lg9/lg8)/(lg3/lg2)=(2lg3/3lg2)/(lg3/l

(log8 9/log2 3)=?
(log8 9/log2 3)=?

(log8 9/log2 3)=?
方法一
(log8 9/log2 3)
=(lg9/lg8)/(lg3/lg2)
=(2lg3/3lg2)/(lg3/lg2)
=(2/3)*(lg3/lg2)/(lg3/lg2)
=2/3
方法二
(log8 9/log2 3)
=log2^3 3^2/log2 3
=(2/3)log2 3/log 2 3
=2/3
logm^a n^b
=(b/a)logm n

(log8 9/log2 3)=(log8 3^2/log2 3)=(2log8 3/log2 3)=(2log3 2/log3 8)=log8 2

用换底公式
(log8 9/log2 3)
=(lg9/lg8)/(lg3/lg2)
=(2lg3/3lg2)/(lg3/lg2)
=(2/3)*(lg3/lg2)/(lg3/lg2)
=2/3

(log8 9/log2 3)=? log8(9)*log2(3) 求(log2^3+log8^9) 已知log2^3=a.则log8^3= log8^9= log8的9次方/log2的3次方= log8^9/log2^3的值是 log8(9)=a,log2(5)=b,则lg(3)=?括号内为真数 (log8 9/log2 3) =(lg9/lg8)/(lg3/lg2) ,这是为什么尼 求值:log8(底数)9/log2(底数)3 (过程） log2 3=a,则log8 √3=_______ log8 4=?2^(log2 3-2)=? 已知log2（log8^m)=log8(log2^m),求log2^m的平方 若log2(log8 m)=log8(log2 m),则(log2 m)^2 log8的27除以log2的3 对数的平方如何算?log8^9=log2^3^3^2是怎么得来的? 计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号3计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号32 log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9 化简：（log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根)