log8的27除以log2的3
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log8的27除以log2的3log8的27除以log2的3log8的27除以log2的3运用换底公式:log827除以log23=(ln27/ln8)/(ln3/ln2)=(3ln3/3ln2)*(
log8的27除以log2的3
log8的27除以log2的3
log8的27除以log2的3
运用换底公式:
log8 27除以log2 3=(ln27/ln8)/(ln3/ln2)
=(3ln3/3ln2)*(ln2/ln3)
=(ln3/ln2)*(ln2/ln3)
=1
27
log8的27除以log2的3
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