(log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根

log8(9)*log2(3) 计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号3计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号32 log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9 化简：（log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根) (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根 (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根 (log8 9/log2 3)=? 求(log2^3+log8^9) log4 243 - log8 729=?log4 12 - log2 6=? 求值：【log2（3）+log4（9）+log8（27）+log16（81）+log32（243）】—5log2（3/2) 求值：(log4(3)+log8(3))(log3(2)+log3(4))-log2(64) log8^9/log2^3的值是 求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16) 利用换底公式求值：1.log2 25 ×log3 4 ×log5 9 2.（log4 3+log8 3）（log3 2+log9 2） (log4＾3+log8＾3)(log3＾2+log9＾2)+log2＾(32)的1/4次方 (log8^27)/(log4^9)的值 log4(3)+log8(3) 怎么算 log4(3)+log8(3) 怎么相加?