求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/22 19:03:58
求值:(log4^3+log8^9)*(log3^2+log9^16)求值:(log4^3+log8^9)*(log3^2+log9^16)求值:(log4^3+log8^9)*(log3^2+log
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
=(log2^3/log2^4+log2^9/log2^8)*(log3^ 2+log3^16/log3^9)
=(1/2log2^3+1/3log2^9)*(log3^2+1/2log3^16)
=(1/2log2^3+2/3log2^3)*(log3^2+2log3^2)
=log2^3 *3log3^2
=3*log2^3 *log3^2
=3
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
(log3 2+log9 2)*(log4 3+log8 3)求值
求值:(log4(3)+log8(3))(log3(2)+log3(4))-log2(64)
求值(log3(2)+log9(2))*(log4(3)+log8(3))打括号是真数.
求值:【log2(3)+log4(9)+log8(27)+log16(81)+log32(243)】—5log2(3/2)
利用换底公式求值:1.log2 25 ×log3 4 ×log5 9 2.(log4 3+log8 3)(log3 2+log9 2)
(log8^27)/(log4^9)的值
log4(3)+log8(3) 怎么算
log4(3)+log8(3) 怎么相加?
(log4(3)+log8(3))*log3(2)
求值:log8(底数)9/log2(底数)3 (过程)
已知4^a=3 代数式log8(9)-2^(log4(3))用a表示为
log3 4×log4 8×log8 a=log根号3 9,则a=
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的?
求值.(log3^2+log9^3)*(log4^3+log8^3)+(log3^3^1/2)^2+ln根号下e-lg1我实在是算不好了,要命啊急滴,
(log3^2 + log9^4)×(log4^3 + log8^3)
计算log9(根号2)*[log4(3)+log8(3)]
化简(log4(3)+log8(3))(log3(2)+log9(2))