(log3^2 + log9^4)×(log4^3 + log8^3)
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(log3^2+log9^4)×(log4^3+log8^3)(log3^2+log9^4)×(log4^3+log8^3)(log3^2+log9^4)×(log4^3+log8^3)首先解释一下l
(log3^2 + log9^4)×(log4^3 + log8^3)
(log3^2 + log9^4)×(log4^3 + log8^3)
(log3^2 + log9^4)×(log4^3 + log8^3)
首先解释一下ln4=2ln2
底数也有类似规律
log4^3=1/2（log2^3）
所以
(log3^2 + log9^4)×(log4^3 + log8^3)
= (log3^2 + log3^2)×(（1/2）log2^3 + （1/3）log2^3)
=5/3
(log3 2+log9 4)*(log4 3+log8 3)
=(lg2/lg3+lg4/lg9)*(lg3/lg4+lg3/lg8)
=(lg2/lg3+2lg2/2lg3)*(lg3/2lg2+lg3/3lg2)
=(3lg2/lg3)*(lg3/2lg2+lg3/3lg2)
=(3lg2/lg3)*(3lg3/6lg2+2lg3/6lg2)
=(3lg2/lg3)*(5lg3/6lg2)
=3*5/6
=5/2
log3*2/log9*4
log3*2/log9*4=?
化简(log3 4)/(log9 8)
(log3^2 + log9^4)×(log4^3 + log8^3)
为什么log9 (9/2)=log3(81/4)
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))
求（log2^3+log8^9)(log3^4+log9^8+log3^2)的值
log3 5-log3 15+1/2log9 27 的值
(log3,4+log9,4)log4,3—log2,2根号2 这怎么解答了
-5log9 4+log3 32/9-5^log5 3-(1/64)^-2/3
计算：-5log9^4+log3^32/9-5log5^3-(1/64)^-2/3
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)(log三次根号4 8)
为什么log9(2)=log3(2)/2如题
解log81(X)+log9(X)+log3(X) < 7/4
(log3 2+log9 2)*(log4 3+log8 3)求值
化简(log4(3)+log8(3))(log3(2)+log9(2))
|log3(5)-2|+log9(25)+(1/32)^1/5
计算log9底8分之log3底2