log3*2/log9*4
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log3*2/log9*4log3*2/log9*4log3*2/log9*4log3*2/log9*4=log32/(log34/log39)=log32/[(log34)/2]=2log32/(l
log3*2/log9*4
log3*2/log9*4
log3*2/log9*4
log3*2/log9*4
=log3 2/(log3 4/log3 9)
=log3 2/[(log3 4)/2]
=2log3 2/(log3 4)
=2log3 2/(2log3 2)
=1
log3*2/log9*4
log3*2/log9*4=?
化简(log3 4)/(log9 8)
(log3^2 + log9^4)×(log4^3 + log8^3)
为什么log9 (9/2)=log3(81/4)
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))
求(log2^3+log8^9)(log3^4+log9^8+log3^2)的值
log3 5-log3 15+1/2log9 27 的值
(log3,4+log9,4)log4,3—log2,2根号2 这怎么解答了
-5log9 4+log3 32/9-5^log5 3-(1/64)^-2/3
计算:-5log9^4+log3^32/9-5log5^3-(1/64)^-2/3
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)(log三次根号4 8)
为什么log9(2)=log3(2)/2如题
解log81(X)+log9(X)+log3(X) < 7/4
(log3 2+log9 2)*(log4 3+log8 3)求值
化简(log4(3)+log8(3))(log3(2)+log9(2))
|log3(5)-2|+log9(25)+(1/32)^1/5
计算log9底8分之log3底2