log3 5-log3 15+1/2log9 27 的值
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log35-log315+1/2log927的值log35-log315+1/2log927的值log35-log315+1/2log927的值log35-log315+1/2log927=log35
log3 5-log3 15+1/2log9 27 的值
log3 5-log3 15+1/2log9 27 的值
log3 5-log3 15+1/2log9 27 的值
log3 5-log3 15+1/2log9 27
=log3 5-log3 15+1/2(lg27/lg9)
=log3 (5÷15)+1/2(3lg3/2g3)
=log3 (1/3) +1/2*3/2
=log3 3^(-1)+1/2*3/2
=-1+3/4
=-1/4
log3 5-log3 15+1/2log9 27
=log3(5/15)+1/2(log3 27 / log3 9)
=log3(1/3)+1/2*3/2
=-1+3/4
=-1/4
log3 5-log3 15+1/2log9 27
=log3 5-log3 (3x5)+1/2log3 27/log3 9
=log3 5-log3 3-log3 5+1/2*3/2
=-1+3/4
=-1/4
log3 5-log3 15+1/2log9 27
=log3 5-log3 (3*5)+1/2log3^2 （3^3）
=-1+1/2*(3/2)
=-1/4
log3 5-log3 15+1/2log9 27
=log3 (5/15)+(1/2)log3^2 3^3
=log3 3^(-1) + (3/4)log3 3
=-1+3/4
=-1/4
log3(5/15)+1/2 log3^2(3^3)
log3(1/3)+3/4 log3(3)
-1+3/4=-1/4
-0.25
log3 5-log3 15+1/2log9 27
=log3 5-log3 15+1/2(lg27/lg9)
=log3 (5÷15)+1/2(3lg3/2g3)
=log3 3^(-1)+1/2*3/2
=-1/4
log3 5-log3 15+1/2log9 27 的值
log3(x^2-3)=1+log3(x-5/3)
log2(3)+log3(5)+log3(2)=?
2log3 2-log3 32/9+log3 8-3^2+log3 5
2log3 2-log3 32/9+log3 8-3^2+log3 5 明天要交的
已知log（32）9=p,log（27）25=q,适用p,q表示lg5p=log32(9)=2/5×log2(3)=2/5×1/log3(2)∴log3(2)=2/5pq=log27(25)=2/3×log3(5)∴log3(5)=3q/2lg5=log3(5)/log3(10)=log3(5)/[log3(2)+log3(5)]=15pq/(4+15pq)结果怎么出来的?
log3 18-log3 2=log3 16?
1.若f(10^x)=x,f(3)=2.log3 5×log3 15-(log3 5)^2-log3 5=3.当0
化简log3(5)+log5(3)-log3(15)*log5(15)
计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15
化简:log2 2+log5 1-3^(2log9 5)+(3log3 5)^2+3^log3 2
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
log3为底真数5-log3为底真数15
log3(x-1)+log3(2x+5)=2上题3为底数
2log3 2-log32/9+log3 8-5^log5 3
log3 2+log3 1/2 +lg20 +lg5等于多少
log3（2）+log3（x)=1,则X=?
计算log3[(9^2 * 27^(1/3))/3^(log3 234)]