log3(x^2-3)=1+log3(x-5/3)
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log3(x^2-3)=1+log3(x-5/3)log3(x^2-3)=1+log3(x-5/3)log3(x^2-3)=1+log3(x-5/3)log3(x^2-3)=1+log3(x-5/3)
log3(x^2-3)=1+log3(x-5/3)
log3(x^2-3)=1+log3(x-5/3)
log3(x^2-3)=1+log3(x-5/3)
log3(x^2-3)=1+log3(x-5/3)
log3(x^2-3)=log3(3)+log3(x-5/3)=log3(3x-5)
x^2-3=3x-5
x^2-3x+2=0
(x-1)(x-2)=0
x=1或x=2
log3(x^2-3)=1+log3(x-5/3)
log3(2)+log3(x)=1,则X=?
log3(2)+log3(x)=1,则x=?
log3(3x-1)=log3(x-1)+log3(3+x)的解是如题
关于对数函数log3 (x^2+2)=log3 x+1以log3为底
解方程 log3 (3^x-1)*log3(3^(x-1)-1/3)=2
log3(x-1)+log3(2x+5)=2上题3为底数
log3(9^x-4)=1+log3(3^x+2)解方程.
Y=(log3 3x/x+1) 2的乘方 — log3 9(x+1)/x X log3 (x+1)2的乘方/9x 2的乘方 X是乘令T=log3 x+1/x ,用T表示Y
y=log3(9/x)×log3 3x求值域!
log3 (1-2*3^x)=2x+1
logx 3=1/(log3 x)?为什么?
已知log3(2x-1)
x属于[1/9,27],f(x)=log3(x/27)*log3(3x)的最大值
log3(x-1)+log3(x+1)=1+log3(x+9)的解为
解不等式(2+log3 x)log3 x>log3 (9x)3都是底数
如果log3^(2x+1)=log3^(x^2-2)则x=
解方程log3 (9^x+8) = x+log3 (3^x+1 + 6)