log3(x-1)+log3(2x+5)=2上题3为底数
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log3(x-1)+log3(2x+5)=2上题3为底数log3(x-1)+log3(2x+5)=2上题3为底数log3(x-1)+log3(2x+5)=2上题3为底数log3(x-1)+log3(2
log3(x-1)+log3(2x+5)=2上题3为底数
log3(x-1)+log3(2x+5)=2
上题3为底数
log3(x-1)+log3(2x+5)=2上题3为底数
log3(x-1)+log3(2x+5)=2
log3[(x-1)*(2x+5)]=2
log3(2x^2+3x-5)=log3 9
所以
2x^2+3x-5=9
2x^2+3x-14=0
x=2或-7/2
经定义域检验x=2
log3(x-1)+log3(2x+5)=log3(x-1)(2x+5)=2
(x-1)(2x+5)=8
可解x
log3(x^2-3)=1+log3(x-5/3)
log3(2)+log3(x)=1,则X=?
log3(2)+log3(x)=1,则x=?
已知log3(2x-1)
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