log8的9次方能化简成log2的多少次方

log8的9次方能化简成log2的多少次方 log8^9/log2^3的值是 化简：（log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根) (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根 (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根 log8的9次方/log2的3次方= 已知log2（log8^m)=log8(log2^m),求log2^m的平方 log8的27除以log2的3 log8(9)*log2(3) (log8 9/log2 3)=? 求(log2^3+log8^9) log8 (log2 4根号2)的值是是log8*(log(2 4根号2)) 求（log2^3+log8^9)(log3^4+log9^8+log3^2)的值 （log8 9） /（log2 3）的值.8和2是底数. log8 9/log2 3的值是?重要是过程分析 对数底数变化真数会变化吗例如Log8 9和Log2 X的转化   求(log2)^3+(log5)^3+log5×log8的值. 计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号3计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号32