数列{an}满足a1=1/2,an=(2n-3/2n)an-1,求证：ak

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数列{an}满足a1=1/2,an=(2n-3/2n)an-1,求证：ak数列{an}满足a1=1/2,an=(2n-3/2n)an-1,求证：ak数列{an}满足a1=1/2,an=(2n-3/2n

数列{an}满足a1=1/2,an=(2n-3/2n)an-1,求证：ak
数列{an}满足a1=1/2,an=(2n-3/2n)an-1,求证：ak<1,(k=1,2,3,.n,ak=a1+a2+.an)

数列{an}满足a1=1/2,an=(2n-3/2n)an-1,求证：ak
因为 an=(2n-3/2n)an-1 所以an=1/2an-1 所以an/an-1=1/2 所以数列{an}为等比数列所以an=a1*1/2的（n-1）次方因为a1=1/2所以an=1/2的n次方又因为k=1,2,3,.n,ak=a1+a2+.an 所以ak=1/2的k次方因为1/2的k次方（n=1,2,3,4.n)次方恒小于1 所以ak小于1

是的，ak是小于1。

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