若cos(x+y)cosy+sin(x+y)siny=0,则cosx=
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若cos(x+y)cosy+sin(x+y)siny=0,则cosx=若cos(x+y)cosy+sin(x+y)siny=0,则cosx=若cos(x+y)cosy+sin(x+y)siny=0,则
若cos(x+y)cosy+sin(x+y)siny=0,则cosx=
若cos(x+y)cosy+sin(x+y)siny=0,则cosx=
若cos(x+y)cosy+sin(x+y)siny=0,则cosx=
∵cos(x+y)cosy+sin(x+y)siny=0
==>cos[(x+y)-y]=0 (应用余弦差角公式cos(A-B)=cosAcosB+sinAsinB)
==>cosx=0
∴cosx=0.
根据公式cos(α-β)= cosαcosβ+sinαsinβ
原式 = cos(x+y-y) = cosx = 0
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