x(x+1)-(xx+y)=-3,求(xx+yy)/2-xy的值
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x(x+1)-(xx+y)=-3,求(xx+yy)/2-xy的值x(x+1)-(xx+y)=-3,求(xx+yy)/2-xy的值x(x+1)-(xx+y)=-3,求(xx+yy)/2-xy的值x(x+
x(x+1)-(xx+y)=-3,求(xx+yy)/2-xy的值
x(x+1)-(xx+y)=-3,求(xx+yy)/2-xy的值
x(x+1)-(xx+y)=-3,求(xx+yy)/2-xy的值
x(x+1)-(xx+y)=-3
x^2+x-x^2-y=-3
x-y=-3
(xx+yy)/2-xy
=(x^2+y^2-2xy)/2
=(x-y)^2/2
=(-3)^2/2
=9/2
x(x+1)-(xx+y)=x-y=-3
(xx+yy)/2-xy=1/2（x-y）²=9/2
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