曲线x^2-xy-y^2-3x+4y-4=0与x轴的交点坐标是
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曲线x^2-xy-y^2-3x+4y-4=0与x轴的交点坐标是曲线x^2-xy-y^2-3x+4y-4=0与x轴的交点坐标是曲线x^2-xy-y^2-3x+4y-4=0与x轴的交点坐标是与x轴交点,就
曲线x^2-xy-y^2-3x+4y-4=0与x轴的交点坐标是
曲线x^2-xy-y^2-3x+4y-4=0与x轴的交点坐标是
曲线x^2-xy-y^2-3x+4y-4=0与x轴的交点坐标是
与x轴交点,就是y=0时x的解
把y=0代入方程,得到
x^2-3x-4=0
二次方程解得x=4或-1
所以交点坐标是(-1,0)或(4,0)
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