given that y=(1+4x)e^-2x show that d^2y/dx^2+2dy/dx+xy=0
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giventhaty=(1+4x)e^-2xshowthatd^2y/dx^2+2dy/dx+xy=0giventhaty=(1+4x)e^-2xshowthatd^2y/dx^2+2dy/dx+xy
given that y=(1+4x)e^-2x show that d^2y/dx^2+2dy/dx+xy=0
given that y=(1+4x)e^-2x show that d^2y/dx^2+2dy/dx+xy=0
given that y=(1+4x)e^-2x show that d^2y/dx^2+2dy/dx+xy=0
这句话的意思是已知y=(1+4x)e^(-2x) 证明d^2 y/dx^2+2dy/dx+xy=0
证明:
dy/dx=4e^(-2x)-2(1+4x)e^(-2x)
d^2 y/dx^2=-8e^(-2x)-8e^(-2x)+4(1+4x)e^(-2x)
xy=x(1+4x)e^(-2x)
上三式相加得d^2 y/dx^2+2dy/dx+xy=0
你确定没有其他条件了么? 二次微分跟两倍的一次微分可以全部消掉。 剩下就是xy的问题了,只要证明出xy为0就ok了。
given that y=(1+4x)e^-2x show that d^2y/dx^2+2dy/dx+xy=0
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