g(x)=sin2x+cos2x如何解

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g(x)=sin2x+cos2x如何解g(x)=sin2x+cos2x如何解g(x)=sin2x+cos2x如何解①(y+1)÷4=(x+2)÷3两边乘以123(y+1)=4(x+2)3y+3=4x+

g(x)=sin2x+cos2x如何解
g(x)=sin2x+cos2x如何解

g(x)=sin2x+cos2x如何解
①(y+1)÷4=(x+2)÷3
两边乘以12
3(y+1)=4(x+2)
3y+3=4x+8
3y=4x+5
代入②2x-3y=1
2x-(4x+5)=1
2x-4x-5=1
2x=-6
x=-3
所以3y=4x+5=-7
所以x=-3,y=-7/3

g(x)=√2(sin2x*√2/2+cos2x*√2/2)
=√2(sin2xcosπ/4+cos2xsinπ/4)
=√2sin(2x+π/4)