(x-5)^2 = (3x+1)^2 x^2-10x+25 = 9x^2+6x+1 8x^2+16x-24 = 0 8x^2+16x+8-32 = 0 8(x^2+2x+1)-32 =
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(x-5)^2=(3x+1)^2x^2-10x+25=9x^2+6x+18x^2+16x-24=08x^2+16x+8-32=08(x^2+2x+1)-32=(x-5)^2=(3x+1)^2x^2-1
(x-5)^2 = (3x+1)^2 x^2-10x+25 = 9x^2+6x+1 8x^2+16x-24 = 0 8x^2+16x+8-32 = 0 8(x^2+2x+1)-32 =
(x-5)^2 = (3x+1)^2 x^2-10x+25 = 9x^2+6x+1 8x^2+16x-24 = 0 8x^2+16x+8-32 = 0 8(x^2+2x+1)-32 =
(x-5)^2 = (3x+1)^2 x^2-10x+25 = 9x^2+6x+1 8x^2+16x-24 = 0 8x^2+16x+8-32 = 0 8(x^2+2x+1)-32 =
8(x^2+2x+1)-32
=8(x^2+2x+1)-8*4
=8(x^2+2x+1-4)
=8(x^2+2x-3)=0
(x^2+2x-3)=0
(x+3)(x-1)=0
(x+3)=0, (x-1)=0
x = -3, x = 1
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
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解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1
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