x^2-2xy+y^2+6y+10=0求x,y的值.请写出详细步骤谢谢

x的平方-2xy+y的平方-6y+10=0,求x,y 已知x平方+y平方-10x-6y+34=0求(x-y/x+y)平方/x平方-y平方/xy乘x平方+2xy+y平方/x平方-xy的值 已知x^2+9y^2-2x-6y+2=0,求{-（xy/（x-y）^2}^4*(y^2-xy/x)^3*x^4/y^10/(x/xy-y^2)^5的值 已知x^2-6xy+9y^2=0,求(x-y)/(x+y) 1-2/x+y=xy,4y+6x=xy.求xy的解? 已知实数xy,满足10x²-2xy+y²+6x+1=0,求x+y 已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值? 1.已知x+y=-4,xy=3,求5（2分之1xy+2y）+[6x-(2xy+y-3x)]的值2.已知（x+3）^2+|x-y+10|=0求代数式5x^2y-[2x^2y-(3xy-xy^2)-3x^2]-2xy^2-y^2的值 已知x>0,y>0,且x+6y=5根号xy,求(2x+根号xy-y)分之(x+根号xy+2y)的值 已知:x>0,y>0,且x- 10√xy+25y=0,求2x+√xy+3y/x+√xy-y 已知x+y=-2,求代数式(6xy+10y)+[4x-2(3xy+2y-x)] x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以（x^2+y^2/y)^2的值 若x^2+y^2+2x-6y+10=0,求xy的值 x^2+y^2+2x-6y+10=0,1求xy的值 x^2+y^2+2x-6y+10=0求xy的值 一道初二下学期的数学题x*x+y*y-2x-6y+10=0,求分式[(x+y)(x-y)]/xy的值 已知x-2y=0,求(x/y-y/x)乘xy/x^2-2xy+y^2 已知,x²+xy=14,y²+xy=2(x>y>0)求x+y.x-y