已知4x+1=m(x-2)+n(x-5),求m,n的值

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已知4x+1=m(x-2)+n(x-5),求m,n的值已知4x+1=m(x-2)+n(x-5),求m,n的值已知4x+1=m(x-2)+n(x-5),求m,n的值4x+1=m(x-2)+n(x-5=m

已知4x+1=m(x-2)+n(x-5),求m,n的值
已知4x+1=m(x-2)+n(x-5),求m,n的值

已知4x+1=m(x-2)+n(x-5),求m,n的值
4x+1=m(x-2)+n(x-5
=mx-2m+nx-5n
=(m+n)x+(-2m-5n)
∴﹛m+n=4
-2m-5n=1
解得m=7,n=-3