{4x-3y+z=12,2x-y-z=10,x+2y+z=16;这是一道三元一次方程题,请把解题过程写清楚,用消元法解!kuaikuaikuai

x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, x+2y-z=-5 x+y+2z=-1 3x+4y-2z=-12x+2y-z=3 2x+y+3z=0 4x+z=-4 3x-y+z=4,2z+3y-z=12,x+y+z=6的解 x+y/2=z+x/3=y+z/4 x+y+z=27 x+2y=3x+2z=4y+z 求x:y:z 三元一次方程组解法 4x+y-z=12 x+y+z=26 3x+2y+z=-5 x-y=1 x-y+5z=1 2x-y+z=18 急 急、、、、、、、、、、 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 x+y+z=6 x+2y+3z=14 y+1=z 方程组3x+y-4z=1 2x-y-2z=6 5x+3y-3z= --1/2{负二分之一} x=?y=?z=?3x+2y+z=13 x+y+2z=7 2x+3y-z=12 x=?y=?z=? 方程组 (1) x+2y-3z=12 x-3y+2z= - 13 x-y-z=0 (2) x+ y=z 5x-y+z=18 2x+5y+3z= -1 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 4x+2y+z=5,4x-2y+z=1,z=-15x+2y+z=12,4x+3y+z=13,z=3 解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6} 解方程组2x+3y-z=12,3x-y+z=4,x+y+z=6 {3x-y+z=4,2x+3y-z=12,x+y+z=6 3x-y+z=4,2x+3y-z=12,x+y+z=6