[sin(540-x)/tan(900-x)]*[1/tan(450-x)*tan(810-x)]*[cos(360-x)/sin(-x)]

[sin(540-x)/tan(900-x)]*[1/tan(450-x)*tan(810-x)]*[cos(360-x)/sin(-x)] 化简：sin(540度-X)/tan(900度-X)*1/tan(450度-x)tan(810度-x)*cos(360度-x)/sin(-x) 化简 （sin(540°-x))/(tan(900°-x))*(1/(tan(450°-x)tan(810°-x))*((cos(360°-x))/(sin(-x)) 一道高一三角函数化简.1.sin(540-x)/tan（900-x)2.1/tan(450-x)tan(810-x)3.cos(360-x)/sin(-x)将上面这三个乘起来（450,900等都是度数） lim (x->0) [tan(tan x)-sin(sin x)]/(tan x -sin x) 帮帮哦,原题是这样的：sin(540-x)/tan(900-x) 乘以 1/tan(450-x)tan(810-x) 乘以 cos(360-x)/sin(-x)条件是tanx=2我怎么化简都是得sinx,真是邪门了, 化简①sin（π+α）×cos（3π/α）+sin（π/2+α）×cos（π+α）②sin（540°-x）×cos（x-360°）/tan（900°-x）×tan（450°-x）×tan（810°-x）×sin（-x） lim x->0 (sin x-tan x)/sin (x^3) (1+tan(x))/sin(2x)不定积分 为什么cos(sin(tan x)))=1 求证tan^x-sin^2x=tan^2x*sin^2x tan(x)-sin(x)等价无穷小tan(x)-sin(x)的等价无穷小 证明:(tan^2)x-(sin^2)x=(tan^2)x(sin^2)x sin(540-α)/tan(α-180)*cot(-α-360)/tan(900-α)*cos(720-α)/sin(-α-360) sin(540-α)/tan(α-180)*cot(-α-360)/tan(900-α)*cos(720-α)/sin(-α-360) 证明tan^2x-sin^2x=tan^2 sin^2x 已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x 若x属于零到六分之派,比较tan(tan x),tan(cos x),tan(sin x)的大小并证明