已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/05 19:39:11
已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值已知:(5x+1)/(x-1)(
已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值
已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值
已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值
(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2)
(5x+1)/(x-1)(x-2)=[A(x-2)+11(x-1)]/(x-1)(x-2)=[(A+11)x-(2A+11)]/(x-1)(x-2)
A+11=5
2A+11=-1
A=-6
(5X+1)/(X-1)(X-2)=A(X-2)/(X-1)(X-2)+11(X-1)/(X-1)(X-2)
5X+1=A(X-2)+11(X-1)
5X+1=AX-2A+11X-1
-AX+2A=6X-2
晕死。。2个未知数。。怎么算吖。。
|x+1|-|x|+|x-2|-|-x+3|已知x+2
已知x=2π+1求 |x-1|+|x-2|+|x-3|+|x-4|+|x-5|+|x-6|+|x-7|+|x-8|+|x-9|+|x-10|
已知x=2π+1.求(X-1)+(X-2)+(X-3)+(X-4)+(X-5)+(X-6)+(X-7)+(X-8)+(X-9)+(X-10)
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
已知x*x-5x=14,求(x-1)(2x-1)-(x+1)*(x+1)+1的值
已知实数x满足5x*x-3x-5=0,求代数式5x*x-2x-[1/5x*x-2x-5]的值.
已知实数x满足5x*x-3x-5=0,求代数式5x*x-2x-1/5x*x-2x-5的值.
已知(x-2)(x-5)/(x-3)(x-4)=x+1/x+2,则x=
已知f(x)=x(x-1)(x-2)(x-3)(x-4)(x-5),则f‘(0)为
已知x*x+x-1=0求x*x*x-2x+2010的值
已知x*x+x-1=0 求x*x*x-2x+11=?
已知不等式:x-33-x;x+1/2-x
提取公因式:已知x*x-5x+1=0 求x*x*x-4x*x-4x-1
已知3x*x-x=1,求6x*x*x+7x*x-5x+2000
已知x^5+x^4-5x^3-2x^2+4x-8 求x+1/x已知x^5+x^4-5x^3-2x^2+4x-8 求x+1/x出错了!已知x^4-5x^3+8x^2-5x+1=0 求x+1/x
已知x^25x+1=0,求x^2+x^-2已知x^2×5x+1=0 求x^2+x^-2
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X