已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值
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已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值已知:(5x+1)/(x-1)(
已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值
已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值
已知:(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2),求A的值
(5x+1)/(x-1)(x-2)=A/(x-1)+11/(x-2)
(5x+1)/(x-1)(x-2)=[A(x-2)+11(x-1)]/(x-1)(x-2)=[(A+11)x-(2A+11)]/(x-1)(x-2)
A+11=5
2A+11=-1
A=-6
(5X+1)/(X-1)(X-2)=A(X-2)/(X-1)(X-2)+11(X-1)/(X-1)(X-2)
5X+1=A(X-2)+11(X-1)
5X+1=AX-2A+11X-1
-AX+2A=6X-2
晕死。。2个未知数。。怎么算吖。。
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