(x+2y) (x-2y) (x2+4y2)其中x=2 y=-1
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(x+2y)(x-2y)(x2+4y2)其中x=2y=-1(x+2y)(x-2y)(x2+4y2)其中x=2y=-1(x+2y)(x-2y)(x2+4y2)其中x=2y=-1用平方差原式=(x&sup
(x+2y) (x-2y) (x2+4y2)其中x=2 y=-1
(x+2y) (x-2y) (x2+4y2)其中x=2 y=-1
(x+2y) (x-2y) (x2+4y2)其中x=2 y=-1
用平方差
原式=(x²-4y²)(x²+4y²)
=x4-16y4
=16-16
=0
有没有搞错~~~~~~~这题也好意思问~~~~~~~~··
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