sin^2Xsin^2B+cos^2Xcos^2B-1/2cos2Xcos2B快
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 14:05:08
sin^2Xsin^2B+cos^2Xcos^2B-1/2cos2Xcos2B快sin^2Xsin^2B+cos^2Xcos^2B-1/2cos2Xcos2B快sin^2Xsin^2B+cos^2Xc
sin^2Xsin^2B+cos^2Xcos^2B-1/2cos2Xcos2B快
sin^2Xsin^2B+cos^2Xcos^2B-1/2cos2Xcos2B
快
sin^2Xsin^2B+cos^2Xcos^2B-1/2cos2Xcos2B快
sin^2Xsin^2B+cos^2Xcos^2B-1/2cos2Xcos2B
=sin^2Xsin^2B+cos^2Xcos^2B-1/2(cos^2x-sin^2x)(cos^2B-sin^2B)
= sin^2Xsin^2B+cos^2Xcos^2B-1/2(cos^2xcos^2B-cos^2xsin^2B-sin^2xcos^2B+sin^2xsin^2B)
=1/2 sin^2Xsin^2B+1/2cos^2Xcos^2B+1/2cos^2xsin^2B+1/2sin^2xcos^2B
=1/2sin^2x(sin^2B+cos^2B)+1/2cos^2x(cos^2B+sin^2B)
=1/2sin^2x+1/2cos^2x
=1/2
sin^2Xsin^2B+cos^2Xcos^2B-1/2cos2Xcos2B快
化简sin^2x+sin^2y-sin^2xsin^2y+cos^2xcos^2y
化简sin^2Xsin^2Y+cos^2Xcos^2Y-0.5cos2Xcos2Y
∫(cos√x)dx答案2√xsin√x-2sin√x+c
∫cos2x/(cos^2xsin^2x)
不定积分cos2x/cos^2xsin^2xdx
求不定积分cos^3Xsin^2Xdx
求证 cos*xcos*y + sin*xsin*y + sin*xcos*y + xin*ycos*x = 1cos*xcos*y + sin*xsin*y + sin*xcos*y + sin*ycos*x = 1注意:[*] 的意思是 [ ^2 ]写下左右过程..
cos xsin b-sin xcos b和sin xcos x-
求积分 cos2x/cos^xsin^2x dx求积分cos2x/cos^xsin^2x dx
(x^2cos^2x-sin^2x)/x^2cos^2xsin^2x (x->0)lim (x^2cos^2x-sin^2x)/x^2cos^2xsin^2x (x->0)=lim [cos^2x-(sin^2x/x^2)]/cos^2xsin^2x=lim (cos^2x-1)/sin^2x=lim -sin^2x/sin^2x=-1这样解错在哪啊?小弟感激不尽
化简cos(a-兀)/sin(兀-a) xsin(a-2兀)Xcos(2兀-a)要详细过程!
化简cos(x-兀)/sin(兀-x) xsin(x-2兀)Xcos(2兀-x)求过程!
请问cos2x/(cos^2xsin^2x)怎么算?
∫cos^4xsin^2xdx怎么积分?
关于sin^2x+cos^2x 的应用式子:cos^6x+sin^6x=(cos^2x+sin^2x)(cos^4x-cos^2xsin^x+sin^4x)=(cos^2x+sin^2x)^2-3sin^2xcos^2x 求这两步算法中的具体思路 ps:cos^2x=cosx的二次方
三角函数 同角三角函数关系式 sin²x-sinxcosx+cos²xsin²x-sinxcosx+cos²x tan=2求值的详细步奏
2sin的平方xsin^2(π/8)-cos^2(π/8) 我知道是2sin^2-1 但是不知道怎么计算啊..