已知,如图AB=AC,AD=AE,∠BAC=∠DAE求证:(1)△ABD≌△ACE (2)∠ADB=∠AEC

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已知,如图AB=AC,AD=AE,∠BAC=∠DAE求证:(1)△ABD≌△ACE(2)∠ADB=∠AEC已知,如图AB=AC,AD=AE,∠BAC=∠DAE求证:(1)△ABD≌△ACE 

已知,如图AB=AC,AD=AE,∠BAC=∠DAE求证:(1)△ABD≌△ACE (2)∠ADB=∠AEC
已知,如图AB=AC,AD=AE,∠BAC=∠DAE
求证:(1)△ABD≌△ACE          (2)∠ADB=∠AEC

已知,如图AB=AC,AD=AE,∠BAC=∠DAE求证:(1)△ABD≌△ACE (2)∠ADB=∠AEC
解 答 证明:∵∠BAC=∠DAE,
∴∠BAC+∠CAD=∠DAE+∠CAD,
即∠BAD=∠EAC,
在△ABD和△ACE中
AB=AC
∠BAD=∠EAC
AE=AD
,
∴△ABD≌△ACE.
所以 ∠ADB=∠AEC
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