2x+2y+3z=10且x+3y+5z=1 求2z+y-x的值
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2x+2y+3z=10且x+3y+5z=1求2z+y-x的值2x+2y+3z=10且x+3y+5z=1求2z+y-x的值2x+2y+3z=10且x+3y+5z=1求2z+y-x的值x+3y+5z-(2
2x+2y+3z=10且x+3y+5z=1 求2z+y-x的值
2x+2y+3z=10且x+3y+5z=1 求2z+y-x的值
2x+2y+3z=10且x+3y+5z=1 求2z+y-x的值
x+3y+5z-(2x+2y+3z)=1-10
x+3y+5z-2x-2y-3z=-9
2z+y-x=-9
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
若xyz≠0且4(x/z)-5(y/z)=-2,(x/z)+4(y/z)=3,求x:y:z
若2分之x+y=3分之y+z=5分之x+z 且x+y+z=18 求x,y,z的值
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
X:y:z=2:3:5且x+2y=10求X+y+2z的值
已知xyz不等于0,且{x+3y+5z=0 x2+3y+z=0,则x.x+y.y-2z.2z/3x.3x+2y.2y+z.z=?
x/2=y/3=z/5 x+3y-z/x-3y+z
x+2y+3z=23 y-z=5 x+2z=10
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z
已知x,y,z满足方程组x-2y+z=0 7x+4y-5z=0,且z不等于0,2x²-3y²+z²/y²-2z²的值为?
如果x/2=y/3=z/4,且x+y+z=18,那么x+y-z=?
已知x:y:z=2:3:4,且x-y+z=36,求x+y+z的值.
已知x:y:z=2:3:4且x+z-y=36求x+y+z的值
已知x:y:z=2:3:4,且x+z-y=36.求x+y+z的值