x^2+y^2=a^2,y^2+z^2=a^2三重积分算体积

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x^2+y^2=a^2,y^2+z^2=a^2三重积分算体积x^2+y^2=a^2,y^2+z^2=a^2三重积分算体积x^2+y^2=a^2,y^2+z^2=a^2三重积分算体积x^2+y^2=a^

x^2+y^2=a^2,y^2+z^2=a^2三重积分算体积
x^2+y^2=a^2,y^2+z^2=a^2三重积分算体积

x^2+y^2=a^2,y^2+z^2=a^2三重积分算体积
x^2+y^2=a^2,y^2+z^2=a^2所围体积,考虑对称性,每个卦限体积相等,只要还求出第一卦限体积再乘以8即可,
积分区域Ω,在ZOY平面投影是1/4圆,0≤y≤a,
0≤z≤√（a^2-y^2),
0≤x≤√（a^2-y^2),即下限为x=0的平面（YOZ平面）,上限为√（a^2-y^2)的柱面,
V=8∫[0,a]dy∫[0,√（a^2-y^2)]dz∫[0,√（a^2-y^2]dx
=8∫[0,a]dy∫[0,√（a^2-y^2)]（√（a^2-y^2）dz
=8∫[0,a] （a^2-y^2)dy
=8(a^2y-y^3/3) [0,a]
=16a^3/3.

x+y+z=12 x-y+z=2 x-z+y+a=90 x+y+a+z=100,求x y z a 用行列式的性质证明：y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证? (x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之（x-z)(y-z)=?第三部分那个是（y+z-2x)(x-2y+z)分之（x-z)(y-z) 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知：x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值. x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z (a-b)+(-2a-b)=?（x+y-z）+（x-y+z）-（x-y-z）=? (x+y-z)^2-(x-y+z)^2=? (x-y-z)*( )=x^2-(y+z)^2 填空已知x+y+z=3a,（a≠0,x,y,z不全等）.求（x-a)(y-a)+(y-a)(z-a)+(z-a)(x-a)／(x-a)^2+（y-a）^2+（z-a）^2 x+y+z=3a(a不等于0,x,y,z不全相等）求[（x-a)(y-a)+(y-a)(z-a)+(z-a)(x-a)]/[(x-a)^2+(y-a)^2+(z-a)^2] 已知X+Y+Z=3a求(X-a)(Y-a)+(Y-a)(Z-a)+(Z-a)（X-a)/(X-a)2;+（Y-a)2;+（Z-a)2;,a≠0,X,Y,Z不全相等, 分解因式:f(x,y,z)=x^2(y-z)+y^2(z-x)+z^2(x-y) 证明：x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0 z=ln(x+a^-y^2) 对y求导, (y-x)/(x+z-2y)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x+z-2y)的值我已经做到这了：设(X-Y)为a （Z-Y)为b (Z-X)为c则原题= (-a*-c)/-(a+b)(b+c)+ab/-(c+b)(a+c)+c*-b/(-a+c)(a+b) x+2y=3x+2z=4y+z 求x:y:z