已知(x-y+1)^2+|2x+y-7|=0,则x^2-3xy+2y^2的值为?请写出过程,
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已知(x-y+1)^2+|2x+y-7|=0,则x^2-3xy+2y^2的值为?请写出过程,已知(x-y+1)^2+|2x+y-7|=0,则x^2-3xy+2y^2的值为?请写出过程,已知(x-y+1
已知(x-y+1)^2+|2x+y-7|=0,则x^2-3xy+2y^2的值为?请写出过程,
已知(x-y+1)^2+|2x+y-7|=0,则x^2-3xy+2y^2的值为?
请写出过程,
已知(x-y+1)^2+|2x+y-7|=0,则x^2-3xy+2y^2的值为?请写出过程,
因为(x-y+1)^2≥0,|2x+y-7|≥0
而(x-y+1)^2+|2x+y-7|=0,所以x-y+1=0,2x+y-7=0
解这个二元一次方程组,得x=2,y=3
所以x^2-3xy+2y^2=4-18+18=4
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