若(5x-1)/(x+2)(2x-3)=M/(x+2)+N/(2x-3),求NM的值

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若(5x-1)/(x+2)(2x-3)=M/(x+2)+N/(2x-3),求NM的值若(5x-1)/(x+2)(2x-3)=M/(x+2)+N/(2x-3),求NM的值若(5x-1)/(x+2)(2x

若(5x-1)/(x+2)(2x-3)=M/(x+2)+N/(2x-3),求NM的值
若(5x-1)/(x+2)(2x-3)=M/(x+2)+N/(2x-3),求NM的值

若(5x-1)/(x+2)(2x-3)=M/(x+2)+N/(2x-3),求NM的值
M/(x+2)+N/(2x-3)
=[M(2X-3)+N(X+2)]/(x+2)(2x-3)
=[(2M+N)X+(2N-3M)]/(x+2)(2x-3)
∵(5x-1)/(x+2)(2x-3)=M/(x+2)+N/(2x-3),
∴2M+N=5
2N-3M=-1
解得M=11/7,N=13/7

M/(x+2)+N/(2x-3)
=[M(2X-3)+N(X+2)]/(x+2)(2x-3)
=[(2M+N)X+(2N-3M)]/(x+2)(2x-3)
∵(5x-1)/(x+2)(2x-3)=M/(x+2)+N/(2x-3),
∴2M+N=5
2N-3M=-1
解得M=11/7,N=13/7
nm=11/7*13/7=143/49