求值cos5π/8cosπ/8解cos5π/8cosπ/8,请写出过程.
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/29 04:55:42
求值cos5π/8cosπ/8解cos5π/8cosπ/8,请写出过程.求值cos5π/8cosπ/8解cos5π/8cosπ/8,请写出过程.求值cos5π/8cosπ/8解cos5π/8cosπ/
求值cos5π/8cosπ/8解cos5π/8cosπ/8,请写出过程.
求值cos5π/8cosπ/8
解cos5π/8cosπ/8,请写出过程.
求值cos5π/8cosπ/8解cos5π/8cosπ/8,请写出过程.
cos(5π/8+π/8)=cos5π/8cosπ/8-sin5π/8sinπ/8=-√2/2
cos(5π/8-π/8)=cos5π/8cosπ/8+sin5π/8sinπ/8=0
两式相加2cos5π/8cosπ/8=-√2/2
cos5π/8cosπ/8=-√2/4
cos5π/8cosπ/8
=[cos(5π/8+π/8)+cos(5π/8-π/8)]/2
=(cos3π/4+cosπ/2)/2
=(cos3π/4)/2
=-√2/4
求值cos5π/8*cosπ8
求值cos5π/8cosπ/8解cos5π/8cosπ/8,请写出过程.
求值:cos5π/8cosπ/8=
sinπ/8*cos5π/8
cos5分之π×cos5分之2π
2倍角公式求值》cosπ/12 x cos5π/12
计算cos5分之π+cos5分之2π+cos5分之3π+cos5分之4π
cos5π等于=
计算cos5分之π+cos5分之2π+cos5分之3π+cos5分之4π
求值:(cosπ/8)^4+(cos3π/8)^4+(cos5π/8)^4+(cos7π/8)^4=正确答案是3/2,我想知道解题过程,自己解了很多遍都不对!谢谢!
求值:cosπ/7cos2π/7cos3π/7cos4π/7cos5π/7cos6π/7
RT,求值cosπ/11*cos2π/11*cos3π/11*cos4π/11*cos5π/11
用欧拉公式e^(ix)=cosx+isinx求值cosπ/7+cos3π/7+cos5π/7
cosπ/12*cos5π/12结果是1/4
cos5π的三角函数值,
cosπ/11×cos2π/11×cos3π/11×cos4π/11×cos5π/11=?求值cosπ/11×cos2π/11×cos3π/11×cos4π/11×cos5π/11=?求值 最后几步由sin6π/11×cos5π/11到sin10π/11怎样变得
求值cosπ/11*cos2π/11*cos3π/11*cos4π/11*cos5π/11求详细过程和重要步骤的原因(1/4*sin8π/11*cos3π/11*cos5π/11)/2sinπ/11=(1/4*sin3π/11*cos3π/11*cos5π/11)/2sinπ/11这一步骤是怎么变过来的
反三角函数求值arccos(cos5π/4)=?arctan(tan4π/3)=?arcsin(sin6)=?