cos(3π/2-α)=sinα求证

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cos(3π/2-α)=sinα求证cos(3π/2-α)=sinα求证cos(3π/2-α)=sinα求证cos(3π/2-α)=-cos(3π/2-α-π)=-cos(π/2-α)=-sinα原式

cos(3π/2-α)=sinα求证
cos(3π/2-α)=sinα
求证

cos(3π/2-α)=sinα求证
cos(3π/2-α)= -cos(3π/2-α -π)= -cos(π/2-α) =-sinα
原式错的