sin^23π/8-cos^23π/8过程
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 07:41:12
sin^23π/8-cos^23π/8过程sin^23π/8-cos^23π/8过程sin^23π/8-cos^23π/8过程sin^23π/8-cos^23π/8应用三角函数半角定理=(1-cos3
sin^23π/8-cos^23π/8过程
sin^23π/8-cos^23π/8过程
sin^23π/8-cos^23π/8过程
sin^23π/8-cos^23π/8 应用三角函数半角定理
=(1-cos3π/4)/2-(1+cos3π/4)/2
=(1-cos3π/4-1-cos3π/4)/2
=-cos3π/4
=(根号2)/2
sin^23π/8-cos^23π/8过程
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
sinπ/8×cosπ/8
sinπ/8×cosπ/8
sinπ/8*cosπ/8
sinπ/8cosπ/8=( )
(cosπ/8+sinπ/8)(cos^3π/8-sin^3π/8)
(cosπ/8+sinπ/8)(cos^3π/8-sin^3π/8).
(cos π/8+ sin π/8 ) (cos^3 π/8+sin^3 π/8 )的值.
cos 5π/8 cos π/8 + sin 5π/8 sin π/8=
8sin(π/32)cos(π/32)cos(π/16)cos(π/8),求值
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8!急救急救
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π)
cos^6(π/8)-sin^6(π/8)=求值,[cos^2(π/8)-sin^2(π/8)][cos^4(π/8)+sin^4(π/8)+cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-[sin^2(π/4)]/4]==7√2/16
cos(-23π/4)+sin(37π/6)
计算sin²π/8-cos²π/8=
cos平方π/8-sin平方π/8,
sin²π/8 -cos²π/8