cos 5π/8 cos π/8 + sin 5π/8 sin π/8=
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cos5π/8cosπ/8+sin5π/8sinπ/8=cos5π/8cosπ/8+sin5π/8sinπ/8=cos5π/8cosπ/8+sin5π/8sinπ/8=cos5π/8cosπ/8+si
cos 5π/8 cos π/8 + sin 5π/8 sin π/8=
cos 5π/8 cos π/8 + sin 5π/8 sin π/8=
cos 5π/8 cos π/8 + sin 5π/8 sin π/8=
cos 5π/8 cos π/8 + sin 5π/8 sin π/8
=cos(5π/8-π/8)=cos(4π/8)=cos(π/2)=0
原式
=cos(5π/8-5π/8)
=cos0
=1
cos(π/32)*cos(π/16)*cos(π/8)=
cos（5π/8）*cosπ/8
cos(5π/8)*cos（π/8)=
化简cos^8(π/8)+cos^8(3π/8)+cos^8(5π/8)+cos^8(7π/8)
cos^2 π/8+cos ^2 3π/8+ cos^2 5π/8+cos^2 7π/8=?
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
cos(π/17)*cos(2π/17)*cos(4π/17)*cos(8π/17)
函数 (4 20:28:50)cos^4 (π /8)+cos^4(3π/8)+cos^4(5π/8)+cos^4(7π/8) =
不用计算器,求(cos(π/8))^4+(cos(3π/8))^4+(cos(5π/8))^4+(cos(7π/8))^4的值
0.5-cos^2(π/8)
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8!急救急救
COS(π/17)COS(2π/17)COS(4π/17)COS(8π/17)要过程
8sin(π/32)cos(π/32)cos(π/16)cos(π/8),求值
cos 5π/8 cos π/8 + sin 5π/8 sin π/8=
计算：cos（π/5)+cos（2π/5)+cos(3π/5)+cos(4π/5)
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值：cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)