一道分式方程,要过程,急!5x/(x^2-10x+24)+(2x-5)/(x^2-x-12)=(7x-10)/x^2-6x+8

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一道分式方程,要过程,急!5x/(x^2-10x+24)+(2x-5)/(x^2-x-12)=(7x-10)/x^2-6x+8一道分式方程,要过程,急!5x/(x^2-10x+24)+(2x-5)/(

一道分式方程,要过程,急!5x/(x^2-10x+24)+(2x-5)/(x^2-x-12)=(7x-10)/x^2-6x+8
一道分式方程,要过程,急!
5x/(x^2-10x+24)+(2x-5)/(x^2-x-12)=(7x-10)/x^2-6x+8

一道分式方程,要过程,急!5x/(x^2-10x+24)+(2x-5)/(x^2-x-12)=(7x-10)/x^2-6x+8
5x/(x^2-10x+24)+(2x-5)/(x^2-x-12)=(7x-10)/(x^2-6x+8)
5x/(x-4)(x-6)+(2x-5)/(x-4)(x+3)=(7x-10)/(x-4)(x-2)
方程两边同乘以(x-2)(x+3)(x-4)(x-6),得
5x(x-2)(x+3)+(2x-5)(x-2)(x-6)=(7x-10)(x+3)(x-6)
5x(x^2+x-6)+(2x-5)(x^2-8x+12)=(7x-10)(x^2-3x-18)
5x^3+5x^2-30x+2x^3-16x^2+24x-5x^2+40x-60=7x^3-21x^2-126x-10x^2+30x+180
7x^3-16x^2+34x-60=7x^3-31x^2-96x+180
15x^2+130x-240=0
3x^2+26x-48=0
用求根公式求
解得:
x=(-13±√313)/3.
经检验,x=(-13±√313)/3是符合要求的实根.

通分啊~