x+y+z=3,3x-y-4z=-2,2x+3y-2z=3用代入法
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x+y+z=3,3x-y-4z=-2,2x+3y-2z=3用代入法x+y+z=3,3x-y-4z=-2,2x+3y-2z=3用代入法x+y+z=3,3x-y-4z=-2,2x+3y-2z=3用代入法就
x+y+z=3,3x-y-4z=-2,2x+3y-2z=3用代入法
x+y+z=3,3x-y-4z=-2,2x+3y-2z=3
用代入法
x+y+z=3,3x-y-4z=-2,2x+3y-2z=3用代入法
就写成X=3-Y-Z代入后两个方程,化为了二元一次方程组,
最后答案貌似是x=y=z=1
z=3-x-y 带入后式化简得:
7x+3y=10;
4x+5y=9;
解得:
x=1
y=1
z=1
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
2x+z=10 x+y-z=4 3x-y-z=0
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
x/2=y/3=z/5 x+3y-z/x-3y+z
若x+y+z=3y=2z,则x/x+y+z=?
3x-y+z=4,2z+3y-z=12,x+y+z=6的解
x/2=y/3=z/4,则x+2y-z/z=?
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
x+y=5 2x+3y-z=9 x-y+z=4
{2x+y=10 {x-y+z=4 {3x-y-z=0
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值