已知函数f(x)=sin(2x+π/6)+sin(2x-π/6)+cosx+a,,1.求最小正周期2.求f(x)的单调增区间3 求f(x)的最大值及此时x值4.若当x∈【0,2/派】时,f(x)的最小值为2,求a
来源:学生作业帮助网 编辑:六六作业网 时间:2025/02/02 16:09:46
已知函数f(x)=sin(2x+π/6)+sin(2x-π/6)+cosx+a,,1.求最小正周期2.求f(x)的单调增区间3求f(x)的最大值及此时x值4.若当x∈【0,2/派】时,f(x)的最小值
已知函数f(x)=sin(2x+π/6)+sin(2x-π/6)+cosx+a,,1.求最小正周期2.求f(x)的单调增区间3 求f(x)的最大值及此时x值4.若当x∈【0,2/派】时,f(x)的最小值为2,求a
已知函数f(x)=sin(2x+π/6)+sin(2x-π/6)+cosx+a,
,1.求最小正周期
2.求f(x)的单调增区间
3 求f(x)的最大值及此时x值
4.若当x∈【0,2/派】时,f(x)的最小值为2,求a
已知函数f(x)=sin(2x+π/6)+sin(2x-π/6)+cosx+a,,1.求最小正周期2.求f(x)的单调增区间3 求f(x)的最大值及此时x值4.若当x∈【0,2/派】时,f(x)的最小值为2,求a
f(x)=sin(2x+π/6)+sin(2x-π/6)+cos2x+a
= sin2xcosπ/6+cos2xsinπ/6 + sin2xcosπ/6-cos2xsinπ/6 + cos2x + a
= 2sin2xcosπ/6 + cos2x + a
= √3sin2x+cos2x+a
= 2(sin2xcosπ/6+cos2xsinπ/6) + a
= 2sin(2x+π/6) + a
最小正周期 = 2π/2 = π
2x+π/6∈(2kπ-π/2,2kπ+π/2)时单调增,∴单调递增区间(kπ-π/3,kπ+π/6),其中k∈Z
最大值2+a,此时2x+π/6=2kπ+π/2,即x=kπ+π/6,其中k∈Z
x∈[0,π/2]时,2x+π/6∈[-π/6,5π/6],2x+π/6=-π/6时最小值2sin(-π/6)+a=-1+a=2,a=3
已知函数F(X)=SIN(2X+φ)(-π
已知函数f(x)=sin(2x+π/6)+sin(2x+π/6)+2cos²x
已知函数f(x)=cos^2(x-π/6)-sin^2x化简
已知函数f(x)=sin^2(x-π/6)+sin^2(x+π/6),若x∈[-π/3,π/6],求函数f(x)的值域
已知函数f(x)=2根号3sin平方x-sin(2x-π/3)
已知函数f(x)=2sin(2x+π/6)求函数f(x)的最大值
已知函数f(x)=[2sin(x-π/6)+√3sin x]cos x+sin^2x,x∈R
已知函数f(x)=2sin(ax-π/6)sin(ax+π/3)
已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4)
已知函数f(X)=2sin(x+π/6)-2cosx 若0
已知函数f(x)=2sin(2x+π/6)+a+1.
已知函数f(x)=2sin(ωx+φ-π/6)(0
已知函数f(x)=cos2x/[sin(π/4-x)]
已知函数f(x)=sin(2x+φ) (0
已知f(x)=2sin(2x+π/6) 函数y=f(x+fai)(0
已知函数f(x)=sin(2x+π/2)+sin(2x-π/6)+cos2x+1,求f(x)的最小正周期,对称轴
已知函数f(x)=sin(x+π/6)+2sin∧2 x/2,求f(x)最大值
已知函数f(x)=4sinx-2/1+sin²x 证明f(x+2π)=f(x)