已知f(x)是定义在(-1,1)上的偶函数,且在[0,1)为增函数,若f(a-2)-f(4-a^2)

已知f(x)是定义在(-1,1)上的偶函数,且在[0,1)为增函数,若f(a-2)-f(4-a^2)
已知f(x)是定义在(-1,1)上的偶函数,且在[0,1)为增函数,若f(a-2)-f(4-a^2)

已知f(x)是定义在(-1,1)上的偶函数,且在[0,1)为增函数,若f(a-2)-f(4-a^2)
-1 -1< a-2< 1
1 -1< 4-a^2 < 1
=> -1< 4-a^2 and 4-a^2 < 1
=> a^2 < 5 and a^2 > 3
=> -√5

自己算

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f(a-2)-f(4-a^2)<0
f(a-2)-f(2+a)（2-a）<0 （0.1）为增， （1，-1）为偶，，，
自己算啊