设y=√x,则dy=?

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设y=√x,则dy=?设y=√x,则dy=?设y=√x,则dy=?y=x^(1/2)dy=(1/2)x(-1/2)dxdy=(1/2)*(x^-1/2)dx1/(2根号x)dxdy=1/2x∧-1/2

设y=√x,则dy=?
设y=√x,则dy=?

设y=√x,则dy=?
y=x^(1/2)
dy=(1/2)x(-1/2)dx

dy=(1/2)*(x^-1/2)dx

1/(2根号x)dx

dy=1/2x∧-1/2 dx
(1/2x的负1/2次方)