求y=3sin(2x+π/3)x∈[-π/6.π/6]的最大值,最小值集对应的x的取值范围

已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值 求导数 y=sin^2(2x+π/3) y=sin(x+π/3)+2定义域怎么求? 1.y=x*e^(2x) 2.y=(sin(2x))/x 3.y=sin(3x+(π/3))怎么求导数! y=sin(2x-π/3) x∈(π/2,π)求值域 y=sin(2x+π/6),x∈[π/4,3π/4]求值域 求函数的值域y=sin(2x+π/3),x∈(-π/6,π) 求y=sin(2x+π/6)x∈(0,π/3)的值域 求函数y=3sin(2x+π/4),x∈R的周期 y =(cos^2) x - sin (3^x),求y' y=sin^2x+sin (π/2-x)+3sin^2(3π/2-x)若tanx=0.5.求y值;若x∈【0,π/2】求y值域 求下列函数周期 y=3sin(x/4) x属于Ry=2sin(2x-π/6) 求y=sin（π/3-2x）+cos（π/3+2x）x∈R的最大值 求单调区间:y=sin(3x-π/3) 求y=sin(x-π/3)sinx最大值 求y=4sin(x+π/3)的值域, 判断单调性 y=sin(x-π/6) y=sin(-2x+π/3) y=sin(x^2),求dy/d(x^3)