sin(2x－π/4)－2√2sin^2x 怎么化简?后面2√2sin^2 x 2是平方，x是在下面的。。。2倍根号2乘以sin的平方乘x我化到原式＝√2/2sin2x－√2/2cos2x-√2+√2cos2x

2sin(x+π/4)sin(x-π/4)=? sin^2(π/4 +x) 傅里叶级数作图f（x）=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si sin(x^2)/sin^2x 求导 化简sin^4x-sin^2x+cos^2x 化简:sin^4 x-sin^2 x+cos^2 x 求证:(sin 2x /(1-cos 2x) )·(sin x /(1+sin x))=tan (π/4-x/2). (1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x 化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x sin^2(π/3-x)+sin^2(π/6+x) sin(πx/2)求导 化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x f(x)=（1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)还有一题, 化简sin(-2x) lim(x(sin)^2) sin^2(x)求导 sin(2x)积分 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4)