3(x^2+1)/(x+2)=4(x+2)/(x^2+1)+4用换元法怎么解
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 20:16:29
3(x^2+1)/(x+2)=4(x+2)/(x^2+1)+4用换元法怎么解3(x^2+1)/(x+2)=4(x+2)/(x^2+1)+4用换元法怎么解3(x^2+1)/(x+2)=4(x+2)/(x
3(x^2+1)/(x+2)=4(x+2)/(x^2+1)+4用换元法怎么解
3(x^2+1)/(x+2)=4(x+2)/(x^2+1)+4用换元法怎么解
3(x^2+1)/(x+2)=4(x+2)/(x^2+1)+4用换元法怎么解
令a=(x²+1)/(x+2)
则3a=4/a+4
3a²-4a-4=0
(3a+2)(a-2)=0
a=-2/3,a=2
(x²+1)/(x+2)=-2/3
3x²+3=-2x-4
3x²+2x+7=0
△
令(x^2+1)/(x+2)=y,原式化为3y=4/y+4,解得Y=3或者Y=-2/3,(x^2+1)/(x+2)=3时,解得X=3或者X=-1,(x^2+1)/(x+2)=-2/3时无解,同时因为X+2处于分母位置,X不能为-2,综上X=3或者X=-1
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x
X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4)
x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=?
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
x^5-x^4+x^3-x^2+x-1
(X+1)X(X+2)X(X+3)=504
求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
(x+1)(x+2)(x+3)(x+4)=24
(x-1)(x-2)(x-3)(x-4)=48
(x+1)(x+2)(x+3)(x+4)=24
x-1+x+2+x/3+4x=77
先化简,再求值:(2-x/x^2+x)/(x^2-3x/x^2+2x+1)x(9-x^2/4-2x),其中x=-2