证(a+1/a)^n-(a^n+1/a^n)≥2^n-2

证(a+1/a)^n-(a^n+1/a^n)≥2^n-2 设a,n∈N*证明a^2n-(-a)^n≥(a+1)×a^n 因式分解:a^n+1+a^n+a^n-1 a^n+1+a^n-1-2a^n因式分解 a^n+2+a^n+1-a^n因式分解 a^n+2+a^n+1-3a^n因式分解 a^n-1-a^n+1因式分解 计算a^n(a^n+1+a^n+a^n-1)-a^n-1(a^n+1+a^n-a^n-1) lim((n+1)^a-n^a) (0 (a^n+1)-(a^n-2)等于 (-1)^n*a (-1)^n *a (3a^n+1+6a^n+2-9a^n)/3a^n-1 (6a^n+2 +3a^n+1 -9a^n)/3a^n-1 -a^n-(-5a^n-1)-2(a^n-1-3a^n) （4a^2n-6a^n+1+2a^n)/2a^n 因式分解 计算:(a(1)+a(2)+.+a(n-1))(a(2)+a(3)+.+a(n))-(a(2)+a(3)+.+a(n-1))(a(1)+a(2)+.a(n)) 求通项公式.a(n+1)=2a(n)+n