∑(-1)^(n-1)An=1,∑A(2n-1)=3,则级数∑An=___其中n是1到无穷,A后面是数列下标

数列{an},a1=3,an*a(n+1)=(1/2)^n,求an 数列an中,若a（ n+1）=an+(2n-1)求an 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 已知数列｛an｝中,a(n+1)=an+2^n,a1=3,求an An=1 A(n+1)=0.5(An+2/An) 求An的极限 a1=1,a(n+1)=2an+n^2+2n +2 求an A1=1,A(n+1)/An=(n+2)/n,求An? 已知a1=2 a(n+1)=2an+2^n+3^n 求an a(n+2)=(2+i^2n)an+1+i^2n,求an a(n+1)=2an+2^n-1. An>0,A1=2,当n>=2,An+A(n-1)=n/(An-A(n-1))+2,求An通项 An>0,A1=2,当n>=2,An+A(n-1)=n/(An-A(n-1))+2,求An通项 an-a(n-1)=2n-10 求通项公式 a(n+1)=an+2n怎样用待定系数法求通项 设级数∑An收敛,且lim(nAn)=a,证明∑n(An-A(n+1))收敛 已知数列{an},当n∈N*时都有an>0,且an^2≤an-a(n+1),证明an {An}中,A1=1,An=A(n-1)+2n,(n>=2)求{An}通项 an中,a1=2,a(n+1)=3an+3(n+1)次方-2n次方,求an