∫(y的取值范围0到27) (2+y/27-y^(1/3))dy∫(y的取值范围0到27) (2+y/27-y^(1/3))dy

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∫(y的取值范围0到27)(2+y/27-y^(1/3))dy∫(y的取值范围0到27)(2+y/27-y^(1/3))dy∫(y的取值范围0到27)(2+y/27-y^(1/3))dy∫(y的取值范

∫(y的取值范围0到27) (2+y/27-y^(1/3))dy∫(y的取值范围0到27) (2+y/27-y^(1/3))dy
∫(y的取值范围0到27) (2+y/27-y^(1/3))dy
∫(y的取值范围0到27) (2+y/27-y^(1/3))dy

∫(y的取值范围0到27) (2+y/27-y^(1/3))dy∫(y的取值范围0到27) (2+y/27-y^(1/3))dy
∫ [2+y/27-y^(1/3)] dy
=2∫dy+(1/27)∫ydy-∫y^(1/3)dy
=2y+(1/27)[y²/2]-[y^(4/3)/(4/3)]
=2(27)+(1/27)(27²/2)-27^(4/3)/(4/3)
=54+27/2-81/(4/3)
=54+27/2-243/4
=27/4=6.75,你的答案没错