y=sin^2-cosx+1最小值为

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y=sin^2-cosx+1最小值为y=sin^2-cosx+1最小值为y=sin^2-cosx+1最小值为y最小值为0.y=sin^2-cosx+1=1-cos^2x-cosx+1=9/4-(cos

y=sin^2-cosx+1最小值为
y=sin^2-cosx+1最小值为

y=sin^2-cosx+1最小值为
y最小值为0.
y=sin^2-cosx+1=1-cos^2x-cosx+1=9/4 - (cosx-1/2)^2.因为cosx取值范围是【-1,1】,所以当cosx=-1时,f渠道最小值,此时y=9/4 - (-1x-1/2)^2=0.