(log2)2+log2*log50+1g25值
来源:学生作业帮助网 编辑:六六作业网 时间:2024/10/07 17:57:33
(log2)2+log2*log50+1g25值(log2)2+log2*log50+1g25值(log2)2+log2*log50+1g25值[log2]2+log2*log50+log25=log
(log2)2+log2*log50+1g25值
(log2)2+log2*log50+1g25值
(log2)2+log2*log50+1g25值
[log2]2+log2*log50+log25
=log2(log2+log50)+log25
=log2(log(2*50))+log25
=2log2+log25
=log2^2+log25
=log(4+25)
=2
背公式loga+logb=logab,nloga=loga^n
(log2)2+log2*log50+1g25值
[log2]2+log2乘log50+log25
(log5)^2+(log2)(log50)=?
(log5)^2+log2·log50
log25+lg2*log50+(log2)^2
高一数学(log5)^2+log2·log50
(log5)+(log2)(log50)的值!急用,谢咯!
【初中数学】求(log5)^2+(log2)(log50)的值.
【初中数学】(log5)^2+(log2)(log50),求手写,
log2 SQR(7/48)+log2 12 -1/2log2 42
log2 SQR(7/48)+log2 12 -1/2log2 48
|[log2(x)]^2-3log2(x)+1|
log2(2X-1)
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
化简log2 1/2+log2 2/3+log2 3/4+.+log2 31/32
计算:(1)log2 (4^3*8^5);(2)log2 3+log2 6-log2 9
(log2) ^2 - log5 *log20课本上 等于 (log2)^2 +(1+log2)(1-log2) = 1;(log2)^2 +(1+log2)(1-log2) 是怎么来的?
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204